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European Baccalaureate revision guide

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S1 · Mathematics

How do I solve 3x + 5 = 20?

1. You want x on its own. Start by taking away the 5 on the left, then do the same on the right so the scales stay balanced.

3x + 5 − 5 = 20 − 5, so 3x = 15.

2. Now 3x means “3 lots of x”. Split both sides into 3 equal parts.

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School years, S1 to S7Language sectionsEuropean Schools coveredGrounded in official EURSC syllabi

Same question, two answers

S7 · Mathematics 5 periods

Show that x = 5 is the only real solution of 3x + 5 = 20.

1. Rearranging: 3x = 15, hence x = 5.

2. The map f(x) = 3x + 5 is affine with gradient 3 ≠ 0, therefore strictly increasing on ℝ and injective.

3. An injective function takes the value 20 at most once, so x = 5 is the unique real solution.

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School years, S1 to S7
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Language sections
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European Schools covered
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Grounded in official EURSC syllabi

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